A Block Of Mass 1Kg Is Stopped Against A Wall. Both weight and this force along the wall the wall. Since the block is held against a wall, the coefficient of friction will be equal to the weight of the block.
Solved: The Co-efficient Of Friction Are As Follows: 0.25 ... from d2vlcm61l7u1fs.cloudfront.net
If they were kept locked up longer and given longer prison sentences in the first place, this city would be a much safer place to live. The problem is solvable if you say that $f_{gravitational}$ = $f_{normal / wall}$, but why is this true? A block has a mass of 1 kg and is placed on a vertical wall such that the coefficient of static friction is 0.5.
Newton's second law of motion.
A block of 1 kg is stopped. The free body diagram of the block is as shown in fig. Here, a picture will help. I will start with a force diagram.
